Question

A sollid piece of iron in the form of a cuboid of dimensions 49cm × 33 cm× 24 cm , is moulded to form a solid sphere. find the radius of the sphere ​

Answer 1

21.00 cm to the nearest hundredth.

Explanation:

The volume of the sphere will be equal to the volume of the cuboid.

So 4/3 π r^3 = 49*33*24 where r = radius of the sphere.

r^3 = (49*33*24 ) / 4/3 π

r^3 = 38808 / 4.18879

= 9264.728

r = ∛9264.728

= 21.0028 cm.

Answer 2

• Radius of sphere is 21 cm

Explanation:

Given:

• A sollid piece of iron in the form of a cuboid of dimensions 49cm × 33 cm× 24 cm , is moulded to form a solid sphere.

To Find:

• Radius of the sphere

Solution:

Volume of sphere = Volume of cubiod

↠ 4/3 πr³ = LBH

↠ 4/3 × 22/7 × r³ = 49 × 33 × 24

↠ 4/3 × 22/7 × r³ = 38808

↠ 4 × 22/7 × r³ = 38808/3

↠ r³ = 38808 × 3 × 7/4 × 22

↠ r³ = 441 × 21

↠ r³ = 9261

↠ r = 21 cm

Hence,

• Radius of sphere is 21 cm