Question

1. Find the length of X and Y:

2. Find the area of the equilateral triangle:

Answer 1

Explanation:

1)

`\sin(theta) = (opposite \: side)/(hypotenuse)`

`\sin(30) = (x)/(10) = (1)/(2)`

`(x )/(1) = (10)/(2)`

`x = 5`

In right Angles traingle

By using Pythagoras theorm

we get

x²+y²=10²

25+y²=100

y²=75

y=5√3

x=5,y=5√3

2)

Area of equilateral traingle =

`( √(3) )/(4) {a}^(2)`

required area

`( √(3) )/(4) * {6}^(2)`

`(36 √(3) )/(4)`

`9 √(3)`