The volume of a balloon f a gas at 842 mm Hg and -23 celsius if it’s volume is 915 milliliters at a pressure of 1170 mm Hg And a temperature of 24 celsius is 0.22 litres
Step-by-step explanation:
Data given:
Initial volume of the balloon having gas V1= 915ml OR 0.195 L
initial pressure of the gas P1= 1170 mm Hg OR 1.53 atm
initial temperature of the gas T1 = 24 celsius or 273.15 + 24 = 297.15 K
Final pressure of the gas P2 = 842 mm Hg or 1.10 atm
final temperature of the gas T2 = -23 degrees or 273.15 - 23 = 250.15 K
Final volume at final temperature and pressure V2=?
The formula used is of Gas Law:
=
![(P2V2)/(T2)](https://img.qammunity.org/2021/formulas/chemistry/college/ldh5ohnqjb9dwkwhvmr2d5ei8m2tpfldbf.png)
V2 =
![(P1V1T2)/(T1P2)](https://img.qammunity.org/2021/formulas/chemistry/college/hixg5lwvqnrv5f98wd13qni436hg6g2l9x.png)
putting the values in the equation:
V2 =
![(1.53 X 0.195 X 250.15)/(297.15 X 1.10)](https://img.qammunity.org/2021/formulas/chemistry/high-school/mhsfvmo9s1hj5y2nja4axm0y5pcw9m4pa7.png)
V2 = 0.22 litres is the volume
The volume is 0.22 litres at a pressure of 1170 mmHg and temperature of -23 degrees.