Question

You randomly guess the answers to two questions on a multiple-choice test. Each question has three choices: A, B, and C.

a. What is the probability that you guess the correct answers to both questions?

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Question 2
Write the probability as a percent. Round your answer to the nearest tenth.
The probability is about
%.
Question 3
b. Suppose you can eliminate one of the choices for each question. How does this change the probability that your guesses are correct?

It increases the probability that your guesses are correct to 14, or 25%, because you are only choosing between 2 choices for each question.

It increases the probability that your guesses are correct to 16, or about 16.7%, because you are only choosing between 2 choices for each question.

It increases the probability that your guesses are correct to 12, or 50%, because you are only choosing between 2 choices for each question.

Being able to eliminate one of the choices does not affect the probability that your guesses are correct because each question still has 3 choices.






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Answer 1

ai) 1/9

ii) 11.1%

b) option 1

Explanation:

Out of three options, one would be correct

Both correct:

1/3 × 1/3 = 1/9

1/9 × 100 = 11.1%

b) if one is eliminated,

two options left with one correct

1/2 × 1/2 = 1/4

1/4 × 100 = 25%

Answer 2

Hello,

This question I've just been jotting down, so I won't explain much. If you want more, just comment!

:D

a. There is only one correct answer for both. Since each question has 3 outcomes, we will have 1 over 3(3). That's 1/9

Thus, a is 1/9.

(about 11.11%

b. If you eliminate one of the choices, then there will be two possible outcomes. We will have 1 over 2(2), so 1/4.

Thus, b is 1/4.

(a in options)

Hope this helps!

(I'm not sure if you just want these answered or the others.)