Question

If a current flowing through a lightbulb is 0.75 ampere and the voltage difference across the lightbulb is 120 volts, how much resistance does the light bulb have

Answer 1

Answer:
`160 \Omega`

Step-by-step explanation:

According to Ohm's law:

`V=R.I`

Where:

`V=120 V` is the voltage difference across the light bulb

`R` is the resistance of the light bulb (the value we want to find)

`I=0.75 A` is the electric current

Isolating
`R`:

`R=(V)/(I)`

`R=(120 V)/(0.75 A)`

Finally:

`R=160 \Omega` This is the resistance of the light bulb