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Jenelle invested $14600 in two mutual funds Fund A earned 5% profit during the first year, while Fund B suffered a 2.5% loss. If she received a total of $430 profit, how much had she invested in each mutual fund?

User Ryryan
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1 Answer

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Answer:

Therefore she invested $10600 and $4000 in Fund A and Fund B respectively.

Explanation:

Given that,

Jenelle invested $14600 in two mutual funds.

Fund A 5% profit during the first year.

Fund B suffered a 2.5% loss.

Let she invested $x in Fund A.

Then the amount of remaining money is =$(14600-x)

So, she invested $(14600-x) in fund B.

Since Fund A 5% profit during the first year.

The amount of profit from fund A is

= Invest amount in fund A × 5%

=
x* 5\%


=x* (5)/(100)


=(5x)/(100)

Since Fund B suffered a 2.5% loss.

The amount of loss in fund B is

=Invest amount in fund B ×2.5%

=(14600-x)×2.5%


=(14600-x)* (2.5)/(100)

Total profit

= Amount of profit - Amount of loss


=(5x)/(100)-(14600-x)* (2.5)/(100)


=(5x-(14600-x)2.5)/(100)


=(5x-36500+2.5x)/(100)


=(7.5x-36500)/(100)

According to the problem,


(7.5x-36500)/(100)=430


\Rightarrow 7.5x -36,500=430* 100


\Rightarrow 7.5x =43000+36,500


\Rightarrow 7.5x =79,500


\Rightarrow x =(79,500)/(7.5)

⇒x=10,600

She invested in fund B = $(14600-10600)=$4000

Therefore she invested $10600 and $4000 in Fund A and Fund B respectively.

User Dave Shinkle
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