Answer:
The area of the larger circle is 9 times greater than that of the smaller circle.
Explanation:
Let d be the diameter of the smaller circle and d be the diameter of the larger circle. If d₁ = 3d
Since Area of a circle A = πd²/4 ⇒ A ∝ d²
Let A be the area of the smaller circle and A₁ be the area of the larger circle.
So, A₁/A = d₁²/d² = (3d)²/d² = 9
A₁/A = 9
A₁ = 9A
So the area of the larger circle is 9 times greater than that of the smaller circle.