Given:
The base of the given figure = 23.8 ft
Height of the parallelogram = 15 ft
To find the area of the shaded region.
Formula
where,
be the area of the shaded region
be the area of the parallelogram.
be the area of the triangular part.
- The area of triangle
where, b be the base and h be the height.
- The area of the parallelogram
![A_(1) =( base)(height)](https://img.qammunity.org/2021/formulas/mathematics/high-school/u66j0iwvsbk7b2i3gc869xsyesp2r5bdu9.png)
- By Pythagoras theorem,
![hypotenuse^(2) = base^(2)+height^(2)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/3zq9f0oi9cr6sfbh3rtnirben80dryba4b.png)
Now,
Putting, Base = 21, Hypotenuse = 23.8 we get,
![Height^(2) = 23.8^(2)-21^(2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/ui9fyy88uhdhrw69av10j5c4vwpqy35ghq.png)
or,
![Height = √(566.44-441)](https://img.qammunity.org/2021/formulas/mathematics/high-school/5k1cx0luitdgag3bw89093mwrmu6foq5mv.png)
or,
![Height = 11.2](https://img.qammunity.org/2021/formulas/mathematics/high-school/e8l1aoitryu4nctsg90ga1xfhkau213iih.png)
Therefore,
Area of the parallelogram
sq ft = 357 sq ft
Area of the triangle
=
sq ft = 117.6 sq ft
So,
The area of the shaded part = (357-117.6) sq ft = 239.4 sq ft
Hence,
The area of the shaded part is 239.4 sq ft.