Answer:
Q cuts the diagonal PA into 2 equal halves, since the diagonals of rhombus meet at right angles.
The value of x is 8.
Explanation:
Given that Quadrilateral CAMP below is a rhombus. the length PQ is (x+2) units, and the length of QA is (3x-14) units
From the given Q is the middle point, which cut the diagonal PA into 2 equal halves.
By the definition of rhombus, diagonals meet at right angles.
Implies that PQ = QA
x+2 = 3x - 14
x-3x=-14-2
-2x=-16
2x = 16
dividing by 2 on both sides, we will get,
![x =(16)/(2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/ug9jl6olhoh8df7zodcii0j0l03ohh84ia.png)
∴ x=8
Since Q cuts the diagonal PA into 2 equal halves, since the diagonals of rhombus meet at right angles we can equate x+2 = 3x-14 to find the value of x.
The line segment
![\overrightarrow{PA}=\overrightarrow{PQ}+\overrightarrow{QA}](https://img.qammunity.org/2021/formulas/mathematics/high-school/7c70b497ydl17nqpfq3ei92ji8deq0mjpg.png)
![\overrightarrow{PA}=x+2+3x-14](https://img.qammunity.org/2021/formulas/mathematics/high-school/mirnwnpy8utr4iu6xi14kc0exura9n1dbv.png)
![=4x-12](https://img.qammunity.org/2021/formulas/mathematics/high-school/u3gev4lml75p1e5xio85fb2l5vfjaceg8o.png)
( since x=8)
![=32-12](https://img.qammunity.org/2021/formulas/mathematics/high-school/cpe8lnqw7qkl1vovqi4gb9bw9bdqmfv78s.png)
![=20](https://img.qammunity.org/2021/formulas/mathematics/high-school/xynt5fr92j4f03rxq152vqk4f6m6oo0xxq.png)
∴
units