Question

CaCO3 + 2HCl --> CaCl2 + CO2 + H2O What mass of carbon dioxide is produced when 21 moles of HCl reacts with excess calcium carbonate?​

Answer 1

The answer to your question is 462 grams

Step-by-step explanation:

Data

mass of CO₂ = ?

moles of HCl = 21

Balanced chemical reaction

CaCO₃ + 2HCl ⇒ CaCl₂ + CO₂ + H₂O

Process

1.- Calculate the moles of CO₂ produced using proportions

2 moles of HCl --------------- 1 mol of CO₂

21 moles of HCl --------------- x

x = (21 x 1) / 2

x = 21 / 2

x = 10.5 moles of CO₂

2.- Calculate the molar mass of CO₂

CO₂ = 12 + (16 x 2) = 12 + 32 = 44 g

3.- Convert the moles of CO₂ to grams

44 g of CO₂ ---------------- 1 mol

x ---------------- 10.5 moles

x = (10.5 x 44) / 1

x = 462 grams