Answer:
The computer be worth after 5 years = $ 66 (option B)
Explanation:
The price of computer = 850
The price of computer after 2 years = 306
By compound depreciation,
... (i)
where Pn = 306
P = 850
R = rate of interest to be calculated
T = 2( number of years)
substituting the values in equation (1), we get

0.6 = 1 -

R = 40%
The worth after 5 years =

Pn = 850 (0.077)
= $66.096 = $ 66
The computer be worth after 5 years = $ 66 (option B)