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a sample of nitrogen gas is at a temperature of 50.0 *C and at a pressure of 2.00 atm. if the volume of the sample remains constant and the pressure increases to 3.20 atm, what is the new temperature of the nitrogen gas?

User Fred Grott
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2 Answers

6 votes

Answer:

516.8 K or 243.8 C

Step-by-step explanation:

- First figure out which gas law to use. In this case we need to use Gay-Lussac's law. This is P1/T1 = P2/T2.

- Next, we need to rearrange this to fit our problem. We should do...

T2 = T1P2/P1

- Now, we need to find our variables. For example...

T1 = 323 K

P1 = 2.00 atm

P2 = 3.20 atm

Next, fill in these numbers to fit our equation. For example...

T2 = 323 x 3.20 / 2.00 = 516.8 K

Note, you did not specify whether you wanted final answer in K or C, so I will put both. I suggest using K if nothing is stated for what they want.

- Hope this helps! If you need a more in-depth explanation please let me know.

User Bigblind
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5.4k points
2 votes

Answer:244

Step-by-step explanation:

a sample of nitrogen gas is at a temperature of 50.0 *C and at a pressure of 2.00 atm-example-1
User Kacper Wolkowski
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5.8k points