Explanation:
It is given that, The product of 2 consecutive even integers is 528 and we have to find the value of each integers.
- So, Let us assume the 1st consecutive even integer as y and the 2nd as (y + 2)
Now, As it is stated in the question that the product of 2 consecutive even integers is 528, So
![\\ { \longrightarrow \qquad{ \pmb{ \sf { y(y + 2) = 528 }}}} \: \: \\ \\](https://img.qammunity.org/2023/formulas/mathematics/high-school/4wldhqyz1y3xg25atufcfaii3irakgqpsw.png)
![{ \longrightarrow \qquad{ \pmb{ \sf { {y}^(2) + 2y = 528 }}}} \: \: \\ \\](https://img.qammunity.org/2023/formulas/mathematics/high-school/aaplk43t1uyrez5ddyumsbzd5n23t2rfyc.png)
Subtracting both sides by 528 we get :
![\\ { \longrightarrow \qquad{ \pmb{ \sf { {y}^(2) + 2y - 528= 528 - 528 }}}} \: \: \\ \\](https://img.qammunity.org/2023/formulas/mathematics/high-school/ketbg1iuoj2m789e8z7h99hclkf6k1fo9x.png)
![{ \longrightarrow \qquad{ \pmb{ \sf { {y}^(2) + 2y - 528= 0 }}}} \: \: \\ \\](https://img.qammunity.org/2023/formulas/mathematics/high-school/33o9ahr1m9gjh2j9j159ytxege42ba2o6e.png)
We have to find two numbers such that,
![\\ { \longrightarrow \qquad{ \pmb{ \sf { p + q= 24 }}}} \: \: \\ \\](https://img.qammunity.org/2023/formulas/mathematics/high-school/9kcn13tutje1zx7fqyyvgbs5ny11gudwhm.png)
![{ \longrightarrow \qquad{ \pmb{ \sf { p * q= 528 }}}} \: \: \\ \\](https://img.qammunity.org/2023/formulas/mathematics/high-school/xjupbpjdzasfzx6h4n78duy5pi2bmplenp.png)
The two numbers are 24 and 22. So,
![\\ { \longrightarrow \qquad{ \pmb{ \sf { {y}^(2) + (-22y) + 24y - 528= 0 }}}} \\ \\](https://img.qammunity.org/2023/formulas/mathematics/high-school/d0r3942qepa6abblp7523u08mp0lqf82a6.png)
![{ \longrightarrow \qquad{ \pmb{ \sf { {y}(y -22) + 24(y - 22)= 0 }}}} \\ \\](https://img.qammunity.org/2023/formulas/mathematics/high-school/t8xr4xegzgyeshdkzdidff1b7wwlqoy30k.png)
![{ \longrightarrow \qquad{ \pmb{ \sf { (y -22) (y + 24)= 0 }}}} \\ \\](https://img.qammunity.org/2023/formulas/mathematics/high-school/3chdh3inv7yf3uxj4wlb06ri1ci8curmht.png)
- Whether, the value of y is (-24) or 22.
![\:](https://img.qammunity.org/2023/formulas/mathematics/college/2ggh1nmemdo9eckwr4kv18nc6ebnpn2pop.png)
So, The first consecutive even integer is 22.
Now,
![\\ { \longrightarrow \qquad{ \pmb{ \sf {Second \: consecutive \: even \: integer=y \:+2 \: }}}} \\ \\](https://img.qammunity.org/2023/formulas/mathematics/high-school/e535qojlib1j8pop71972blkmjy88ua8du.png)
![{ \longrightarrow \qquad{ \pmb{ \sf {Second \: consecutive \: even \: integer=2 2+2 \: }}}} \\ \\](https://img.qammunity.org/2023/formulas/mathematics/high-school/h1ii6oci76f6amklhx0lu4o96453itn5g3.png)
![{ \longrightarrow \qquad{ \pmb{ \sf {Second \: consecutive \: even \: integer=24 }}}} \\ \\](https://img.qammunity.org/2023/formulas/mathematics/high-school/a8xjbqf771ezcf8dxjcwwahfgg5fnty39g.png)
Therefore,
- The value of each integer is 22 and 24.