Question

Determine the volume, in liters, occupied by 0.015 molecules of oxygen at STp?

Answer 1

5.58 X
`10^(-25)` Litres is the volume, in liters, occupied by 0.015 molecules of oxygen at STP.

Step-by-step explanation:

Data given:

molecules of oxygen = 0.015

number of moles of oxygen =?

temperature at STP = 273 K

Pressure at STP = 1 atm

volume = ?

R (gas constant) = 0.08201 L atm/mole K

to convert molecules to moles,

number of moles =
`(molecules)/(Avagadro's number)`

number of moles = 2.49 x
`10^(-26)`

Applying the ideal gas law since the oxygen is at STP,

PV = nRT

rearranging the equation:

V =
`(nRT)/(P)`

putting the values in the rearranged equation:

V =
`(2.49 X10^(-26) X 0.08201 X 273)/(1)`

V = 5.58 X
`10^(-25)` Litres.