Question

Tristan has some dimes and some quarters. He has at least 20 coins worth at most $4.25 combined. If Tristan has 10 dimes, determine the maximum number of quarters that he could have. If there are no possible solutions, submit an empty answer.

Answer 1

The maximum number of quarters that he could have is 13

Explanation:

Let x represent the number of quarters he could have. If he has 10 dimes and has at least 20 coins, then

→ x + 10 >= 20

→ x >= 10 (1)

His coins worth at most $4.25. Also, it is known that 1 dollar is equal to 100 cents, 1 dime is equal to 10 cents and 1 quarter is equal to 25 cents.

→ (x * 25) + (10 * 10) <= (4.25 * 100)

→ 25x + 100 <= 425

→ 25x <= 325

→ x <= 13 (2)

If we combine the equation 1 and 2:

10 <= x <= 13

The maximum value of x is 13