Given:
In the circle P, ABCD is inscribed quadrilateral.
And, ∠DAB = 110°, ∠ABC = 72°
To find the value of ∠ADC.
Theorem:
A quadrilateral can be inscribed in a circle if and only if the opposite angles are supplementary [ sum of the opposite angles will be 180°]
According to the theorem,
![\angle ABC+\angle ADC = 180^(\circ)](https://img.qammunity.org/2021/formulas/mathematics/high-school/ktnzlnuge14pzqxc04v2xe0nmn68frs67m.png)
![\angle ADC +72^(\circ) = 180^(\circ)](https://img.qammunity.org/2021/formulas/mathematics/high-school/odu1gn86oa95nibl2rz18llhy9rfh6unvg.png)
![\angle ADC = 180^(\circ)-72^(\circ)](https://img.qammunity.org/2021/formulas/mathematics/high-school/ua6n0ah6mjstj9gxin9t502y9qx6r7gz03.png)
![\angle ADC = 108^(\circ)](https://img.qammunity.org/2021/formulas/mathematics/high-school/q2jk20pd5kzw9kech1rdjcf8vah5xrtd38.png)
Hence,
The value of ∠ADC is 108°.
Hence, Option b is the correct answer.