Answer:
The probability that the server is idle is 0.25.
Explanation:
If N (t) is a Poisson process with rate λ, then the inter-arrival times X₁, X₂, ⋯ are independent and the distribution of X
is Exponential (λ).
The arrival rate of customers at a single-server toll booth is:
λ = 90 cars/hour
The service time for each customer is half a minute.
Then the service rate is:

μ = 120 cars/hour
Then the probability statement P ( N (t) = n) there are n customers in the system.
![P ( N (t) = n) =((\lambda)/(\mu))^(n)[1-(\lambda)/(\mu)]](https://img.qammunity.org/2021/formulas/mathematics/college/z62zkoybsx5vyjcf5trh7zym6kqdxo7e3e.png)
Compute the value of P ( N (t) = 0) as follows:
![P ( N (t) = 0) =((90)/(120))^(0)[1-(90)/(120)]](https://img.qammunity.org/2021/formulas/mathematics/college/ofb0lsc98rzblu9diwgjvupw8w4npymjqk.png)
![=1* [(120-90)/(120)]](https://img.qammunity.org/2021/formulas/mathematics/college/zt5i75irkinpol4p2a87sk1bnpkntgjxx1.png)

Thus, the probability that the server is idle is 0.25.