Question

A 350-g baseball is shot out of a small cannon with a velocity of 9.0 m/s. The baseball flies horizontally at a constant height of 3.0 m. What is its angular momentum if its radius is 7.4 cm? (I know the answer is 9.6 kgm^2/s but I don't understand how to get it)

Answer 1

`9.5 kg m^2/s`

Step-by-step explanation:

The angular momentum of an object is given by:

`L=mvr`

where

m is the mass of the object

v is its velocity

r is the distance of the object from axis of rotation

Here we have:

m = 350 g = 0.35 kg is the mass of the ball

v = 9.0 m/s is the velocity

r = 3.0 m is the distance of the object from axis of rotation (if we take the ground as the centre of rotation)

Therefore, the angular momentum is:

`L=(0.35)(9.0)(3.0)=9.5 kg m^2/s`