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The question is in the image

The question is in the image-example-1
User Alitosuner
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12 votes

Check the picture below.

now, keeping in mind that ratio of the sides is the same as the ratio of the perimeters.


\cfrac{\stackrel{small}{trapezoid}}{\stackrel{large}{trapezoid}}\qquad \stackrel{sides}{\cfrac{6}{9}}~~ = ~~\stackrel{perimeters}{\cfrac{20}{p}}\implies \cfrac{2}{3}=\cfrac{20}{p}\implies 2p=60 \\\\\\ p=\cfrac{60}{2}\implies p=30 \\\\[-0.35em] ~\dotfill


\cfrac{\stackrel{small}{trapezoid}}{\stackrel{large}{trapezoid}}\qquad \stackrel{sides^2}{\cfrac{6^2}{9^2}}~~ = ~~\stackrel{areas}{\cfrac{A}{45}}\implies \cfrac{36}{81}=\cfrac{A}{45}\implies \cfrac{4}{9}=\cfrac{A}{45} \\\\\\ 180=9A\implies \cfrac{180}{9}=A\implies 20=A

The question is in the image-example-1
User James Johnston
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