Question

When a single high-resistance (long) bulb is connected to a 1.5 volt battery, the current through the battery is about 80 milliampere. If you add another high-resistance (long) bulb in parallel, the battery current of course increases to 160 milliampere. Select all of the true statements given this situation.

a. The battery is ohmic.
b. The battery is not ohmic.
c. Current through the battery is proportional to ΔV across the battery.
d. Current through the battery is not proportional to ΔV across the battery.
e. The battery always puts out the same current.

Answer 1

In the described scenario, the battery behaves ohmically and the current through it is proportional to the change in voltage across the battery, which remains constant when adding a bulb in parallel. The battery does not always put out the same current; it varies with the circuit's total resistance. So the correct option is a and c.

Step-by-step explanation:

When a single high-resistance bulb is connected to a 1.5-volt battery, the current through the battery is about 80 milliamperes. Adding another high-resistance bulb in parallel, the battery current doubles to 160 milliamperes. In this context, a few conclusions can be drawn:

• The battery appears to be ohmic since the current through it is proportional to the voltage across the connected load. This is because when another bulb is added in parallel, the total resistance of the circuit decreases, and according to Ohm's law (V = IR), the current should increase if the voltage remains constant and the resistance decreases, which is what's observed.
• The current through the battery is certainly proportional to ΔV across the battery. The doubling of current upon adding another bulb in parallel, it suggests that the voltage has remained constant, affirming Ohm's law and indicating a linear relationship between current and voltage (ΔV) across the battery for the given resistance values.
• It's clear that the battery does not always put out the same current; it varies depending on the total resistance of the circuit connected to it.

From these observations, we would select the following statements as true given the situation:

1. The battery is ohmic (a).
2. Current through the battery is proportional to ΔV across the battery (c).

Answer 2

Step-by-step explanation:

When two similar resistances are joined parallel to each other , current becomes two times . It is as per ohm's law. On joining in parallel two equal resistances , total resistances of circuit become half. Hence as per ohm's law , current becomes double. Hence the given resistance is ohmic.

Current through the battery will be same as external current in the circuit . Let it be I . Let the external resistance be R . Let the emf of the battery be E . Potential difference on the battery

ΔV = E - IR

If I increases ΔVdecreases . So there is inverse relation.

Option D is correct .

So option A and D are correct.