Answer:
A.
Explanation:
I would advise finding the difference between 300 and 200 and 450 and 300:
![300-200=100\\450-300=150](https://img.qammunity.org/2023/formulas/mathematics/high-school/ktnc4sgsmc0pxywodo6swbhj61bli7xhl6.png)
We can eliminate C and D since she saves 100 the first month and 150 the second month.
The next step would be to find the increase every month:
![(Final value)/(initial value)=x\\\\(300)/(200)=1.5 \\\\(450)/(300) = 1.5](https://img.qammunity.org/2023/formulas/mathematics/high-school/e31bbwo9e0edy5f0qse68gaqq546xvrjb4.png)
If we would write the increase as a function, we would get:
![y= 1.5x](https://img.qammunity.org/2023/formulas/mathematics/high-school/h339bp6bpgo6g6xy9078jv15vnw1dnkseq.png)
we can check this by substituting values:
![y=1.5*200\\y=300\\\\\\y=1.5*300\\y=450](https://img.qammunity.org/2023/formulas/mathematics/high-school/xmjdqe7ckkpyarn6hjopky0dug5dp0syd9.png)
An exponential function looks like this:
![y= a^x](https://img.qammunity.org/2023/formulas/mathematics/high-school/eo84xpo7wgsb190nebk2gefn7yk5zjqruu.png)
A linear function looks like this:
![y=mx+b](https://img.qammunity.org/2023/formulas/mathematics/high-school/smsb8cbft03lwblmi49nf2l6jby2ofxzws.png)
Our m is 1.5, a linear increase by 150% and our b is 0, which can be written like:
![y=1.5x+0\\y=1.5x](https://img.qammunity.org/2023/formulas/mathematics/high-school/wutf27nafwbugz2icoso6qk1pilv5cvkrj.png)
Therefore our function resembles a linear function more than an exponential function, eliminating answer B.