Question

Of 100 students, 32 are taking Calculus, 29 are taking French, and 13 are taking both Calculus and French, if a student is picked at random

what is the probability that the student is taking Calculus or French?
(Reduce fraction to lowest form)​

Answer 1

The probability that the student is taking Calculus or French =
`(12)/(25)`

Explanation:

The total number of students = 100

Let A represents calculus and B represents French

The no of students taking calculus = 32

The no of students taking French = 29

The no of students taking calculus and french = 13

the probability that the student is taking Calculus or French = ?

P (AUB) = P(A) + P(B) - P(A∩B)

=
`(32)/(100)` +
`(29)/(100)` -
`(13)/(100)`

=
`(48)/(100)`

Reducing to lowest fraction, it becomes
`(12)/(25)`

The probability that the student is taking Calculus or French =
`(12)/(25)`