Answer:
104 J/K
Step-by-step explanation:
First, we have to calculate the heat (Q) involved in the vaporization of 1.00 mol of methanol.
Q = n × ΔH°vap
Q = 1.00 mol × 35.21 kJ/mol = 35.2 kJ
Then, we have to convert the boiling point to Kelvin.
K = °C + 273.15
K = 64.6 + 273.15 = 337.8 K
Finally, we calculate the change in the entropy associated with this process.
ΔS = Q/T
ΔS = 35.2 kJ/337.8 K = 0.104 kJ/K = 104 J/K