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3 votes
Question 7 Multiple Choice Worth 1 points)

(04.02 MC)
What is the solution to the following system of equations?
4x + 2y = 12
x - y = 3
(3, 0)
(0,3)
(0, -3)
(2, 3)

2 Answers

2 votes
A
4(3)+2(0)=12+0=12
3-0= 3
User Mdd
by
8.0k points
4 votes

Answer:

The answer to your question is (3, 0)

Explanation:

Data

4x + 2y = 12 Equation l

x - y = 3 Equation ll

Process

To solve this problem use the elimination method

1.- Multiply equation ll by 2

4x + 2y = 12

2x - 2y = 6

6x 0 = 18

2.- Solve for x

6x = 18

x = 18/6

x = 3

3.- Substitute x in equation ll to find y

3 - y = 3

-Solve for y

-y = 3 - 3

y = 0

4.- Write the solution

(3, 0)

User Akshaynagpal
by
8.1k points

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