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The radius of circle a is 3 in the radius of circle b is 4 in greater than circle a circle c is 4 in greater than circle b the radius of circle d is 3 in less than the radius of circle c what is the area of all of the circles how many times greater than the area of circle a is the area of circle d

2 Answers

5 votes

Answer:

The areas are as follows

a = 28.26 inches^2

b = 153.86 inches^2

c = 379.94 inches ^2

d = 200.96 inches^2

The area of circle d is greater than that of a by about 7 times

Explanation:

Please see the attached files for explanation

The radius of circle a is 3 in the radius of circle b is 4 in greater than circle-example-1
The radius of circle a is 3 in the radius of circle b is 4 in greater than circle-example-2
The radius of circle a is 3 in the radius of circle b is 4 in greater than circle-example-3
User Sven Slootweg
by
7.8k points
7 votes

Answer:

  • Area of Circle A
    =9 \pi
  • Area of Circle B
    =49 \pi
  • Area of Circle C
    =121 \pi
  • Area of Circle D
    =64 \pi
  • The area of circle D is
    7(1)/(9) times greater than the area of circle A.

Explanation:

Circle A

The radius of circle A is 3 in

r= 3 Inch

Area of Circle A
=\pi r^2=3^2*\pi=9 \pi

Circle B

The radius of circle B is 4 inch greater than circle A.

r= 4+Radius of circle A= 4+3 =7 Inch

Area of Circle B
=\pi r^2=7^2*\pi=49 \pi

Circle C

The radius Circle C is 4 in greater than circle b.

r= 4+Radius of circle B= 4+7 =11 Inch

Area of Circle C
=\pi r^2=11^2*\pi=121 \pi

Circle D

The radius of circle D is 3 in less than the radius of circle C.

r= Radius of circle C -3 = 11-3 =8 Inch

Area of Circle D
=\pi r^2=8^2*\pi=64 \pi

Area of Circle A
=9 \pi

Area of Circle D
=64 \pi

Number of Times by which Area of Circle D is greater than Area of Circle A

=
(64 \pi)/(9 \pi) =7(1)/(9)

  • The area of circle D is
    7(1)/(9) times greater than the area of circle A.
User Utiq
by
8.6k points

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