Question

The graph below shows the function f (x) = StartFraction 5 x + 10 Over x squared + 7 x + 10 EndFraction.

On a coordinate plane, a hyperbola is shown. Both curves approach x = negative 5. There is a hole at x = negative 2.

Where is the removable discontinuity of f(x) located?
x = –5
x = 0
x = –2
x = 5

Answer 1

I think that the correct answer is -2, and not -5.

Explanation:

Got it wrong for you guys. Edge 2021.

Answer 2

I believe it would be -5 but, I might be wrong.