Question

A chemist makes 360mL of calcium sulfate working solution by adding distilled water to 90.0mL of a 10.7mmol/L stock solution of calcium sulfate in water. Calculate the concentration of the chemist's working solution. Round your answer to 3 significant digits.

Answer 1

Answer: The concentration of the chemist's working solution is 0.00268 M

Step-by-step explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

According to the neutralization law,

`M_1V_1=M_2V_2`

where,

`M_1` = molarity of stock solution = 10.7 mmol/L = 0.0107 mol/L
`1mmol=10^(-3)mol`

`V_1` = volume of stock solution = 90.0 ml

`M_2` = molarity of working solution = ?

`V_2` = volume of working solution = 360 ml

`0.0107* 90.0=M_2* 360`

`M_2=0.00268M`

Thus the concentration of the chemist's working solution is 0.00268 M