Question

Player a led a. Baseball league and runs battle ends for the 2008 regular season. Player b, Who came in second two player a, had 14 Fewer runs battled in for the 2008 regular season. Together these two players brought home 222 runs during the 2008 regular season. How many runs battled in did player a and b each account for?

Answer 1

A=Player A runs; B=Player B runs=A-16

A+B=242 Substitute for B.

A+A-16=242 Add 16 to each side.

2A=258 Divide each side by 2.

A=129 ANSWER 1: Player A batted in 129 runs.

B=A-16=129-16=113 ANSWER 2: Player B batted in 113 runs

CHECK:

A+B=242

129+113=242

242=242