Answer:
We conclude that the mean lifetime of a certain tire it uses is less than 40,000 miles which means that the trucking firm’s claim was correct.
Explanation:
We are given that a trucking firm suspects that the mean lifetime of a certain tire it uses is less than 40,000 miles.
To check the claim, the firm randomly selects and tests 54 of these tires and gets a mean lifetime of 39,460 miles with a population standard deviation of 1200 miles.
Let
= mean lifetime of a certain tire.
SO, Null Hypothesis,
:
40,000 miles {means that the mean lifetime of a certain tire it uses is more than or equal to 40,000 miles}
Alternate Hypothesis,
:
< 40,000 miles {means that the mean lifetime of a certain tire it uses is less than 40,000 miles}
The test statistics that will be used here is One-sample z test statistics as we know about the population standard deviation;
T.S. =
~ N(0,1)
where,
= sample mean lifetime of 54 tires = 39,460 miles
= population standard deviation = 1200 miles
n = sample of tires = 54
So, test statistics =
= -3.307
Hence, the value of test statistics is -3.307.
Now at 0.05 significance level, the z table gives critical value of -1.6449 at for left-tailed test. Since our test statistics is less than the critical value of t as -3.307 < -1.6449, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region.
Therefore, we conclude that the mean lifetime of a certain tire it uses is less than 40,000 miles which means that the trucking firm’s claim was correct.