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How do you solve number #4?

How do you solve number #4?-example-1
User Smriti
by
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1 Answer

3 votes

Answer:

b

Explanation:

Area of the shaded region =[ (3x-2)(x+3) ] - [ x*6 ]

= 3x*x +3x*3 + (-2)*x + (-2)*3 - 6x

=3x² + 9x - 2x - 6 - 6x {bring like term together}

=3x² + 9x - 2x - 6x - 6

= 3x² + x - 6 {9x - 2x - 6x = 9x - 8x = x}

Area = 24 square units

3x² + x - 6 = 24

3x² + x - 6 - 24 = 0

3x² + x - 30 = 0

Product = 3* -30 = -90

Sum = 1

Factors = 10 , (-1)

3x² + x - 30 = 0

3x² - 9x + 10x - 10*3 = 0

3x*(x - 3) +10*(x - 3) = 0

(x-3)(3x +10) = 0

3x + 10 is ignored because measurements will not be in negative values.

x - 3 = 0

x = 3

User Bosie
by
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