Question

ABCD is a trapezium

Calculate the area of ABCD

Answer 1

This is answer for finding bottom right hand corner angle where 25cm total base length is given. Where given, 4cm height trapezium with central height and central right angle, same format question but different heights as seen here in answer.

Explanation:

AD part length 1 = 8.5² - 4² = √56.25 = 7.5cm

AD part length 2= 25-7.5 = 17.5cm

AD part length 3= 17.5- 5 = 12.5

AD total length = 7.5+ 12.5 + 5 = 25cm

Area = 1/2 x12.5 x 4 = 25

Scalene Triangle 4/12.5 = 0.3 × 4 = 1.2

CD length size = 12.5 ² + 4² = 156.25 + 16 √172.25 = c² = 13.12cm

13.2/12.5 = 1.056 ​

1/2 12.5 = 6.25

1/2 13.12 = 6.51.

6.25+ 6.51 + 4 = 16.76

1.056 x 16.8

CDA angle = 17.7˚

Answer 2

87.5 cm squared

Explanation:

Equation: 1/2h(b1+b2)^2. Add the two bases to get fifteen, multiply that by the height, 7, to get 175, divide that by 2(or multiply it by 1/2)