Question

A student hooks up a voltmeter and an ammeter in a circuit to find the resistance of a light bulb. The ammeter read 3 amps and the voltmeter reads 6 volts. What is the resistance of the light bulb?

Answer 1

`2\Omega`

Step-by-step explanation:

(Assuming the cell in the circuit has 0 internal resistance)

Ohm's Law is given as:

`V=IR`

Voltage is Current multiplied by Resistance.

We can rearrange this formula to give us:

`R=(V)/(I)`

Now we can plug in our values

`R=(6)/(3)=2\Omega`

Answer 2

I= 3A

V= 6V

R=?

V=IR

R=V/I

R=6/3

Therefore R = 2ohms

Hope this will help u mate :)