Question

1. If P(x)= x^4+ ax^2+ bx-6 with P(4)=6 and P(2)=0, find the values of a and b.

Answer 1

a = -4, b = -3

Explanation:

P(2) = 0

= 4a +2b = -10

P(4) = 6

= 16a + 4b = -52

16a + 4b = -52 - 8a + 4b = -20

= 8a = -32

a = -4

b = -3