Question

Rb2SO4 + LiF --> RbF +

Answer 1

`Rb_2 SO_4 + 2LiF \rightarrow 2RbF+ Li_2SO_4`

Step-by-step explanation:

In this problem, we have the equation of a chemical reaction to complete.

The uncomplete equation is:

`Rb_2 SO_4 + LiF \rightarrow RbF+`

In order to complete the equation, the missing compound must include the missing elements, which are:

`SO_4`

`Li`

So the missing compound must be

`LiSO_4`

So now we can write:

`Rb_2 SO_4 + LiF \rightarrow RbF+ LiSO_4`

However, the reaction is not balanced yet, in fact we see that:

- We have 2 atoms of Rb on the left, and 1 atom only on the right

So we add a 2 in front of RbF:

`Rb_2 SO_4 + LiF \rightarrow 2RbF+ LiSO_4`

However, now the F is not balanced, so we also add a 2 in front of LiF:

`Rb_2 SO_4 + 2LiF \rightarrow 2RbF+ LiSO_4`

Finally, we see now that the Li is not balanced, therefore:

`Rb_2 SO_4 + 2LiF \rightarrow 2RbF+ Li_2SO_4`

So now the equation is balanced.