Question

Can anybody help me figure out the area of simple composite figure?

Answer 1

Given:

The length of the rectangle = 16 ft

The width of the rectangle = 12 ft

The diameter of the semicircle = 12 ft

To find the area of the given figure.

Formula

• 
  `A=A_(1) +A_(2)`

where,

`A` be the area of the given figure

`A_(1)` be the area of the rectangle

`A_(2)` be the area of the semicircle.

• The area of the rectangle =
  `lb` where, l be the length and b be the width
• Area of the semicircle =
  `(1)/(2) \pi r^(2)`, r be the radius of the semicircle.

Now,

The radius of the semicircle r = 6 ft

Putting, r=6, l=16 and b= 12 we get,

`A_(1) = (16)(12)` sq ft

or,
`A_(1) = 192` sq ft

`A_(2) = (1)/(2) (3.14)(6^(2) )` sq ft

or,
`A_(2)=56.52` sq ft

So,

`A = 56.52+192` sq ft

`A` = 248.52 sq ft

Rounding off to the nearest tenth, we get;

A=248.5 sq ft.

Hence,

The area of the composite figure is 248.5 sq ft.