Question

Please help me with these square root problems, Part 1. Please show and check the work.


`1. √(2x-5) - √(x+6) =0\\\\2. √(2x-5) + √(x+6)=0\\ \\3. √(x-5) - √(x+6)= 2\\ \\4. √(2x-5) -√(x+6)=2`

Answer 1

x = 11

Explanation:

√2x-5 - √x+6 = 0

√2x-5 = √x+6

(√2x-5)² = (√x+6)²

2x - 5 = x + 6

2x - x = 6 + 5

x = 11

Answer 2

x = 11

Explanation:

sqrt (2x - 5) = sqrt (x + 6)

Square both sides

2x - 5 = x + 6

x = 11

Verify:

sqrt[2(11) - 5] = sqrt(11 + 6)

sqrt(17) = sqrt(17)