Question

The volume of a gas collected when the temperature is 20.0°C and the pressure is 720 mm Hg

measures 0.0228 L. What is the calculated volume of the gas at 28.0°C and 780 mm Hg?

Answer 1

`\large \boxed{\text{21.6 mL}}`

Step-by-step explanation:

We can use the Combined Gas Laws to solve this problem

`(p_(1)V_(1) )/(T_(1)) = (p_(2)V_(2))/(T_(2))`

Data

p₁ = 720 Torr; V₁ = 0.0228 L; T₁ = 20.0 °C

p₂ = 780 Torr; V₂ = ?; T₂ = 28.0 °C

Calculations

(a) Convert the temperatures to kelvins

T₁ = (20.0 + 273.15) K = 293.15 K

T₂ = (28.0 + 273.15) K = 301.15 K

(b) Calculate the new volume

`\begin{array}{rcl}(p_(1)V_(1) )/(T_(1)) & = & (p_(2)V_(2))/(T_(2))\\\\\frac{\text{720 Torr $*$ 0.0228 L}}{\text{293.15 K}} & = & \frac{\text{780 Torr} * V_(2)}{\text{301.15 K}}\\\\\text{0.056 00 L} & = & \text{2.590V}_(2)\\& = & \text{0.0216 L}\\& = & \textbf{21.6 mL}\\\end{array}\\\text{The calculated volume of the gas is $\large \boxed{\textbf{21.6 mL}}$}`