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The parabola y=x^2-2x+4 will have a vertex of

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Answer:

The vertex is at (h, k) => (1, 3)

Explanation:

Complete the square of y=x^2 - 2x + 4 to determine the coordinates of the vertex.

Note that the first two terms of y=x^2 - 2x + 4 resemble the perfect square (x - 1)^2:

y=x^2 - 2x + 4 => y= ( x^2 - 2x + 1 )+ 4 - 1, or

y = (x - 1)^2 + 3

Comparing this last result to the standard equation y = (x - h)^2 + k, we see that h = 1 and k = 3. The vertex is at (h, k) => (1, 3)

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