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What are the zeroes of the function y=3(x-a)(x+b) in terms of a and b?

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Answer:

a, -b

Explanation:

When x is a, the function becomes


f(a)=3(a-a)(a+b)

as you see, a-a is 0, and as your whole function is multiplied by this, it makes it 0.


f(-b)=3(-b-a)(-b+b)

As you see -b+b is 0, and once again, this would make the whole function 0.

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