150k views
0 votes
Help please with this question

Help please with this question-example-1

1 Answer

0 votes

Given:

The given two functions are
f(x)=(4 x^(2)+24 x)/(x^(2)-11 x+30) and
g(x)=(x-5)/(x^(2))

We need to determine the value of R(x)

Value of R(x):

The value of R(x) can be determined by R(x) = f(x) × g(x)

Substituting the values, we get;


R(x)=(4 x^(2)+24 x)/(x^(2)-11 x+30) \cdot (x-5)/(x^(2))

Multiplying the fractions, we have;


R(x)=(\left(4 x^(2)+24 x\right)(x-5))/(\left(x^(2)-11 x+30\right) x^(2))

Let us factor out the common term 4x from the term (4x² + 24x)

Thus, we have;


R(x)=(4 x(x+6)(x-5))/(\left(x^(2)-11 x+30\right) x^(2))

Let us factor the term (x² -11x + 30), we get;


R(x)=(4(x+6)(x-5))/(x(x-5)(x-6))

Cancelling the common term, we have;


R(x)=(4(x+6))/(x(x-6))

Thus, the value of R(x) is
(4(x+6))/(x(x-6))

User Thankyoussd
by
8.6k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories