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How to find the radius with the center of (0,0) passing through (9,5)

User Miyagisan
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3 votes

Answer:

EASY!

Explanation:

So I have not done this type of problem before, but I can help!

So what we need to do is find the distance between those two points, and that's are radius! (because any point on a circle is equidistant, or the same distance away from the center).

To do this, we need to use Pythagorean Theorem:

It's a theorem that states that sum of the squares of the leg's of a right triangle is equal to the square of the hypotenuse.

Here's a little picture if you don't know what I'm talking about:

(the one that is attached to this answer)

So, the radius we are looking for is C.

Now, imagine a right triangle were from one point it draws a horizontal line and from the other endpoint, we draw a vertical line that intersects the horizontal line, and that's our triangle.

Now we also know the 'legs' of the triangle with the info that: 9-0=9, 5-0=5

And we know that A and B are 9 and 5(order does not matter).

So, time to solve!


9^(2) +5^(2) =C^(2)\\√(106) =C\\

Hope this helps!

P.S. Stay Safe!

How to find the radius with the center of (0,0) passing through (9,5)-example-1
User Marco Salerno
by
7.9k points

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