Answer:
x< -6 or x > 0 (C is correct for question 1.) x ≤ 2 (C is correct for question 2)
Explanation:
You have given me 2 questions:
| x + 3 | + 7 > 10
3x + 6 ≤ 12
Let's solve the first one:
| x + 3 | + 7 > 10
Before we start, the greater-than sign means that the point on the number line has to not be filled in.
| x + 3 | + 7 > 10
**Along with this equation you need to do a negative one meaning you need to flip the sign to a less than one and make 10 and 7 negative.
| x + 3 | - 7 < -10
| x + 3 | + 7 > 10
**Notice that this one is the original one.
Subtract 7 both sides
| x + 3 | > 10 -7
Now do 10-7
| x + 3 | > 3
Now subtract 3 both sides
x > 0
The negative case:
| x + 3 | - 7 < -10
Add 7 both sides
| x + 3 | < -10 + 7
Do -10 + 7
| x + 3 | < -3
Subtract 3 both sides
x < -3-3
Solve -3-3
x < -6
Your inequalities:
x< -6 or x > 0
The or statement is for greater than and the "and" is for less than.
Answer Choice C is correct.
Next Question:
3x + 6 ≤ 12
**Before we do anything, we have a less than or equal sign**
The point will be filled on the number line.
This is a typical inequality two-step:
3x + 6 ≤ 12
Subtract 6 from both sides
3x ≤ 12-6
Do 12-6
3x ≤ 6
Now divide 6 by 3
x ≤ 2
Answer Choice C is correct.