Question

Solve the following system of equations please ASAP

Answer 1

Given:

The system of equation:

`x+y = -4` -------- (1)

`y = x^(2) -6x` --------- (2)

To find the values of x and y.

We will use substitution method.

From (1) we get,

`y = -4-x`

We will put the value of y in (1) and we get,

`-x-4 = x^(2) -6x`

or,
`x^(2) -5x+4= 0`

Now we will apply middle term factor method.

`x^(2) -(4+1)x+4 = 0`

`x^(2) -4x-x +4 = 0`

`x(x-4)-1(x-4) = 0`

`(x-4)(x-1)= 0`

so, x = 4 and 1

Now,

Substitute x = 4 in (1) we get,

`y = -4-4 = -8`

And putting x = 1 in (1) we get,

`y = -4-1 = -5`

Hence, the solution of the given system of equation is (4,-8) and (1,-5)

Thus, Option A is the correct answer.