Question

Due on Monday.
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`7n^(2) -7`

Answer 1

7n2-7 = 7 (n -1)(n+1)

Answer 2

Answer: 7(n + 1)(n - 1)

Explanation:

`7n^2-7`

`\mathrm{Rewrite\:}7\mathrm{\:as\:}7\cdot \:1`

`=7n^2-7\cdot \:1`

`$$ Factor out the common term 7`

`=7\left(n^2-1\right)`

`$$ Factor $n^2 - 1`

`\mathrm{Rewrite\:}1\mathrm{\:as\:}1^2`

`=n^2-1^2`

`$$ Apply difference of two squares formula $ x^2 - y^2 = (x+y)(x-y)`

`n^2-1^2=\left(n+1\right)\left(n-1\right)`

`\therefore \bf{7\left(n+1\right)\left(n-1\right)}`