Can someone please help me ASAP

asked Apr 20, 2021 148k views

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by Dinh

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$y=4-x^2\\x-y=2 \\ \\ y = 4 - {x}^(2) \\ x = 2 + y \\ \\ y = 4 - {(2 + y)}^(2) \\ {y}^(2) + 5y = 0 \\ y(y + 5) = 0 \\ y = 0 \\ y = - 5$

x = 2 + 0 = 2

x = 2 + ( - 5) = -3

Frederik Bode answered Apr 25, 2021

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