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What is the vertex and the equation for the axis of symmetry of 4x^2+3x+2

User Masnun
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Answer:

the vertex is at (-3/8, 23/16) and the axis of symmetry is x = 3/8

Explanation:

The coefficients of the given quadratic are a = 4, b = 3 and c = 2.

The axis of symmetry is given by

-b -3

x = ------- which here is x = -------- = -3/8

2a 2(4)

We use this result, x = -3/8, as the divisor in synthetic division to find the y-coordinate of the vertex. Here's how:

-3/8 4 3 2

-3/2 -9/16

---------------------------------

4 3/2 23/16

Thus, we know the vertex is at (-3/8, 23/16) and the axis of symmetry is x = 3/8.

User Jens Tinfors
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