Standard form: ax^2 + bx + c = y
Steps to simplify:
2x^2 - 1 = 3x + 4
~Subtract (3x + 4) to both sides
2x^2 - 1 - 3x + 4 = 3x + 4 - 3x + 4
~Simplify
2x^2 - 3x - 5 = 0
(a = 2, b = -3, c = -5)
Now that we know what these values are, we can use the quadratic formula to solve.

Answer: x = 5/2 or x = -1
Best of Luck!