Question

Find the solution by elimination method.
Please Help. ​

Answer 1

x = 3, y = 2

Explanation:

Multiply equation 1 by -6

-24x - 36/y = -90

Multiply equation 2 by 4

24x - 32/y = 56

Add the two equations:

-36/y - 32/y = -34

-68/y = -34

y = -68/-34

y = 2

4x + 6/2 = 15

4x = 15 - 3

4x = 12

x = 3

Answer 2

I'm newbie here

Explanation:

Elimination Method.

4x + 6/y = 15 → step 1

6x - 8/y = 14 → step 2

so,

4x + 6/y = 15 |×6|

6x - 8/y = 14 |×4|

24x + 6/y(6) = 90

24x - 8/y(4) = 56

24x + 36/y = 90

24x - 32/y = 56

____________ _

68/y = 34

68 = 34y

34y = 68

y = 2

subsitution y = 2 to..

4x + 6/y = 15

4x + 6/2 = 15

4x + 3 = 15

4x = 12

x = 3

So, for x is 3, and for y is 2