Given:
Given that the diameter of the circle is
![(7)/(2) \ cm](https://img.qammunity.org/2021/formulas/mathematics/high-school/iyazidrn4enaqcndgajgvzcswxgzqvh6bw.png)
We need to determine the radius, circumference in terms of π and circumference using π = 3.14.
Radius:
The radius of the circle can be determined using the formula,
![r=(d)/(2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/j6ijg49ycvj0jhupgt61e9fhf04admn2vm.png)
Substituting
, we get;
![r=(((7)/(2)))/(2)}](https://img.qammunity.org/2021/formulas/mathematics/high-school/ggxmzbsr3c6btz34olvgpcztv2224b1l5i.png)
Simplifying, we get;
![r=(7)/(4) \ cm](https://img.qammunity.org/2021/formulas/mathematics/high-school/y1xsc1a4b1y96yq808pfd1zneisi9h57b1.png)
Thus, the radius of the circle is
![(7)/(4) \ cm](https://img.qammunity.org/2021/formulas/mathematics/high-school/5f7cc8hyfkc1m4unewuqcc14a6044kymin.png)
Circumference in terms of π:
The circumference of the circle can be determined using the formula,
![C=2 \pi r](https://img.qammunity.org/2021/formulas/mathematics/middle-school/n7crk4pwg2k5k0e1ze4uua4fv78clnl9ck.png)
Substituting
, we get;
![C=2 \pi ((7)/(4))](https://img.qammunity.org/2021/formulas/mathematics/high-school/ht3goq4bvuje6ng0cz2qrv8cbv2v52xsys.png)
![C=(7)/(2) \pi \ cm](https://img.qammunity.org/2021/formulas/mathematics/high-school/miqbdwhqyn0u9pm2o245ui2uksm012tiz9.png)
Thus, the circumference in terms of π is
![(7)/(2) \pi \ cm](https://img.qammunity.org/2021/formulas/mathematics/high-school/zrvr5ombliumo865r9ozoz4sfzcydfkp7c.png)
Circumference using π = 3.14:
Substituting π = 3.14 in the circumference of the circle
, we get;
![C=(7)/(2)(3.14)](https://img.qammunity.org/2021/formulas/mathematics/high-school/51pklkrasqulff6huf7xl0m5kyr3eha62j.png)
![C=10.99 \ cm](https://img.qammunity.org/2021/formulas/mathematics/high-school/nomjkhi9hwwh4ozls76ud3hxszauq2wfz9.png)
Thus, the circumference of the circle is 10.99 cm