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F(x) = 8-4x+X²
g(x) = 2x² +5x-1
find f(x) + g(x)

User ShintoTuna
by
4.2k points

2 Answers

5 votes

Answer:

IN THE PICTURE

Explanation:

...IN THE PICTURE

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F(x) = 8-4x+X² g(x) = 2x² +5x-1 find f(x) + g(x)-example-1
User Nate Reed
by
4.5k points
1 vote

Answer: "
3x^(2) -4x +7 " .

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Explanation:

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We are to find the following sum:

Add:
f(x) + g(x) .

Given:
f(x)= 8-4x +4x^(2) ;

Rewrite as follows:


f(x) =x^(2)-4x+8 ;

{Note: Since:
f(x) = +8 + (-4x) + x^(2) ; we can rearrange the terms;

and rewrite by starting in the order of the highest degree monomial

(i.e., the term among the 3 (three) monomials containing the variable with the highest exponential value—which is: "
x^(2) " ; and continue in descending order; with "
(-4x^(1))" ; which is: "
-4x " ; [with the 'implied exponent of "1" ; since any value, raised to the exponent, "1" ; ["first power"]; resulting in that same value. Then, we finish with the last monomial, "
(+8x^0) "; which is: "(+8x) " —with the implied exponent of "0" ; since any non-zero value; raised to the "0th" exponent ['raised to the power of zero']; results in the value of "1" .

→ As such: " +8x = +8x⁰ " ;

↔ " +8x⁰ = (+8) * (x⁰) = (+8) * (1) = " (+8) ;

→ {since any value, multiplied by "1" ; results in that same value; this refers to the "identity property" of multiplication.}.

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So, plug in: "
x^(2)-4x+8 " ; for: "
f(x) " ;

And plug in the given: "
2x^(2) + 5x -1 " ; for "
g(x) " ;

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And add the sum:

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f(x) +g(x) = (x^(2)-4x+8)+(2x^2+5x-1) ;

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= x^(2) -4x+8+2x^(2) -1 ;

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→ Now, combine the "like terms" ; and simplify:

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+x^(2) +2x^(2) =+3x^(2) ;


-4x ; stands alone;


+8 -1 = + 7 ;

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→ Now; we have accounted for All of the terms in our expression;

and we can write out our answer:

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→ which is: "
3x^(2) -4x +7 " .

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Hopefully—this answer and explanation is helpful to you.

Wishing you the best in your academic pursuits!

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User Ahmad Ferdous
by
4.0k points